The constant κ for s close to one #
Section 5 of the paper states that, for s close to one, κ ≈ (1 − s²)²/4
(sec5_kappa_proof). With u = s² − 1, κ = {u − log(1 + u)}/2 and (1 − s²)² = u², and the
Taylor expansion log(1 + u) = u − u²/2 + O(u³) gives 2{u − log(1 + u)}/u² → 1
(tendsto_two_mul_sub_log_div_sq).
2{u − log(1 + u)}/u² → 1 as u → 0, u ≠ 0.